You can use an explicit object parameter with a deduced type:
auto dfs = [&](this const auto &self, int x) -> void { // .... self(x);};dfs(0); // `self` is `dfs`This is a C++23 feature
↧
Answer by Artyer for How to write a beautiful inline recursive lambda in C++?
↧
Trending Articles
More Pages to Explore .....